hdu2852-白红宇

hdu2852

阅读量：727 次

发布时间：2019-03-17

本文共 1490 字，大约阅读时间需要 4 分钟。

经过对代码和解释部分的优化，以下是优化后的内容：

#include 
   
    #include 
    
     #include 
     
      #include 
      
       #include 
       
        #include 
        #include 
         
          #include 
          
           #include 
           
            #include 
            
             using namespace std;#define scd(n) scanf("%d", &n)#define scdd(a, b) scanf("%d%d", &a, &b)#define lowbit(x) x & (-x)typedef long long LL;typedef pair
             
               PII;const int N = 1e5 + 7;const int INF = 0x3f3f3f3f;int a[N];int tr[N];int m, k;void add(int x, int c) { for (int i = x; i <= N; i += lowbit(i)) { tr[i] += c; }}LL sum(int x) { LL res = 0; for (int i = x; i > 0; i -= lowbit(i)) { res += tr[i]; } return res;}void solve() { memset(tr, 0, sizeof(tr)); memset(a, 0, sizeof(a)); while (m--) { int p, e; scd(p); if (p == 0) { scd(e); a[e]++; add(e, 1); } else if (p == 1) { scd(e); if (!a[e]) { puts("No Element!"); } else { a[e]--; add(e, -1); } } else { int a_val, k_val; scdd(a_val, k_val); LL s = sum(a_val); int left = 1, right = N; while (left < right) { int mid = left + (right - left) / 2; if (sum(mid) >= s + k_val) { right = mid; } else { left = mid + 1; } } if (sum(left) >= s + k_val) { printf("%d\n", left); } else { puts("Not Found!"); } } }}int main() { // int t; // scd(t); // while (cin >> t) { solve(); // } return 0;}